The following data summarizes results from 941 pedestrian deaths that were caused by accidents. If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was intoxicated or the driver was intoxicated. Pedestrian Pedestrian Intoxicated Not intoxicatedDriver Intoxicated 56 71Driver Not intoxicated 292 522

Answer:P=0.3698  or 36.98%Step-by-step explanation:Complete the table by adding the totals to each column and row.                                 Pedestrian     Pedestrian                                 Intoxicated    Not intoxicated Totals Driver Intoxicated           56                     71               127 Driver Not intoxicated   292                   522             814 Totals                            348                    593             941 The probability that the pedestrian was intoxicated or the driver was intoxicated is the opposite event of neither of them was intoxicated.  The total of cases when neither of them was intoxicated is 593. So the probability is: P1=593/941=0.6302 The probability of the opposite event is one minus the probability calculated: P=1-0.6302=0.3698 And this is the probability that the pedestrian was intoxicated or the driver was intoxicated.