Q:

Suppose that a classroom has 8 light bulbs. The probability that each individual light bulb works is 0.8. Suppose that each light bulb works independently of the other light bulbs. What is the probability that all eight of the light bulbs work? a.0.17 b.0.13 c.0.00001024d.0.8

Accepted Solution

A:
Answer:a. 0.17Step-by-step explanation:Total number of light bulbs = 8The probability that each individual light bulb works = 0.8The working of light bulbs is independent of each other, this means one light bulb does not influence the other light bulbs. We need to calculate the probability that all eight of the light bulbs work. Since the light bulbs work independently, the overall probability of independent events occurring together is the product of their individual probabilities. Therefore,Probability that all eight of the light bulbs work = 0.8 x 0.8 x 0.8 x 0.8 x 0.8 x 0.8 x 0.8 x 0.8= [tex](0.8)^{8}[/tex]= 0.16777216β‰ˆ 0.17Thus, option a gives the correct probability that all eight of the light bulbs work