MATH SOLVE

2 months ago

Q:
# PLEASE HELPPP!!!! WILL GIVE BRAINLIEST!!!h(t)=β16t^2+28tThe function h(t) gives the approximate height, in feet, of a dolphin's jump out of water, where t represents the time, in seconds. What is the total length of time, in seconds, it took the dolphin to complete one jump? Show your work.

Accepted Solution

A:

We find the zeros of h(t), which is where the height is 0. When the height is zero, the dolphin will be in the water.

Set h(t) = 0

0=-16t^2+28t

Factor out -4t:

0= -4t(4t - 7)

The zeros, by zero factor property we set every factor to zero and combine solutions

t = 0 .. or ... 4t - 7 = 0

t = 0 .. or ... 4t = 7

t = 0 .. or ...Β Β t = 7/4

t = 0 .. or ...Β Β t = 1.75

since h(t)=β16t^2+28t is a parabola that opens down the dolphin gets out of the water at t = 0 and then gets back in at t = 1.75 (the vertex of their height is in between).

The total length is 1.75 seconds

Set h(t) = 0

0=-16t^2+28t

Factor out -4t:

0= -4t(4t - 7)

The zeros, by zero factor property we set every factor to zero and combine solutions

t = 0 .. or ... 4t - 7 = 0

t = 0 .. or ... 4t = 7

t = 0 .. or ...Β Β t = 7/4

t = 0 .. or ...Β Β t = 1.75

since h(t)=β16t^2+28t is a parabola that opens down the dolphin gets out of the water at t = 0 and then gets back in at t = 1.75 (the vertex of their height is in between).

The total length is 1.75 seconds