A bag of 29 tulip bulbs contains 10 red tulip bulbs, 12 yellow tulip bulbs, and 7 purple tulip bulbs. (a) What is the probability that two randomly selected tulip bulbs are both red? (b) What is the probability that the first bulb selected is red and the second yellow? (c) What is the probability that the first bulb selected is yellow and the second red? (d) What is the probability that one bulb is red and the other yellow?
Accepted Solution
A:
Answergiven,A bag consist of 29 tulip bulbsa) P(both bulb are red ) = =[tex]P(first\ red\ bulb) \times P(second\ red\ bulb)[/tex] = [tex]\dfrac{10}{29} \times \dfrac{9}{28})[/tex] = 0.111 P(both bulb are red ) = 0.111b) P(first bulb is red and second yellow ) = = [tex]P(first\ red\ bulb) \times P(second\ yellow\ bulb)[/tex] = [tex]\dfrac{10}{29} \times \dfrac{12}{28})[/tex] = 0.148 P(first bulb is red and second yellow ) = 0.148c) P(first bulb is yellow and second red ) = =[tex]P(first\ yellow\ bulb) \times P(second\ red\ bulb)[/tex] =[tex]\dfrac{12}{29} \times \dfrac{10}{28})[/tex] =0.148 P(first bulb is yellow and second red ) = 0.148d) P(one bulb is red and the other yellow) = = P(first bulb is yellow and second red ) + P(first bulb is red and second yellow ) = 0.148 + 0.148 = 0.296P(one bulb is red and the other yellow) = 0.296